$200 Bing Ad Coupons

[tunescool]

i have 2 $200 Bing Ad coupons that can be used for new accounts only, you can only use a debit/credit card to redeem it

if you havent used Bing Ads before and have affiliates on your blogs or sell other products or services there is NO REASON why you wouldnt want this

its $200 worth of Ads on the top of the first page of Bing, that people searching for your products will see, and are already interested in your stuff

the minimum bid for an ad is 5 cents, you only pay when someone goes to your site

$20 for one coupon - $200

PM me

 

[Gus]

you can only use a debit/credit card to redeem it

Sounds fishy.

 

[tunescool]

talk stupid in your own threads pal

 

[Gus]

talk stupid in your own threads pal

That wasn't very nice.

 

[Steve Jobs]

Why so cheap?

 

[tunescool]

Why so cheap?

thats about what they go for anywhere theyre sold, websites that sell them, or just people on fiver or wherever

i dont personally sell them but ive used one already and they wont accept my other cards on bing so i cant open a new account to use one

 

[tunescool]

That wasn't very nice.

the cards are used to verify your accounts and have a payment option in place to pay for ads later. i mentioned it because paypal is an option but these coupons are only for cards

 

[Gus]

That wasn't very nice.

the cards are used to verify your accounts and have a payment option in place to pay for ads later. i mentioned it because paypal is an option but these coupons are only for cards

To you use your own word, its pretty "stupid" that these things only accept credit/debit cards on the internet where alternative payment methods are widely accepted pretty much everywhere you go. I'll return to my original comment and say that it sounds fishy to me and there was nothing stupid about what I said. It was a valid observation.

 

[Lord Saru]

That is enough. Let us get back to the topic. If you wish to discuss the autheticity of this offer, you may do so through PMs.

For the rest of you who might have the same question, @tunescool had given the answer in his previous post.